Trending ▼  

GATE 2013 : Biotechnology

14 pages, 65 questions, 18 questions with responses, 23 total responses
gate
  
+Fave Message
 Home > gate >

Formatting page ...
 

2013 BIOTECHNOLOGY BT BT:BIOTECHNOLOGY Duration: Three Hours Maximum Marks:100 Please read the following instructions carefully: General Instructions: 1. Total duration of examination is 180 minutes (3 hours). 2. The clock will be set at the server. The countdown timer in the top right corner of screen will display the remaining time available for you to complete the examination. When the timer reaches zero, the examination will end by itself. You will not be required to end or submit your examination. 3. The Question Palette displayed on the right side of screen will show the status of each question using one of the following symbols: You have not visited the question yet. You have not answered the question. You have answered the question. You have NOT answered the question, but have marked the question for review. You have answered the question, but marked it for review. The Marked for Review status for a question simply indicates that you would like to look at that question again. If a question is answered and Marked for Review, your answer for that question will be considered in the evaluation. Navigating to a Question 4. To answer a question, do the following: a. Click on the question number in the Question Palette to go to that question directly. b. Select an answer for a multiple choice type question. Use the virtual numeric keypad to enter a number as answer for a numerical type question. c. Click on Save and Next to save your answer for the current question and then go to the next question. d. Click on Mark for Review and Next to save your answer for the current question, mark it for review, and then go to the next question. e. Caution: Note that your answer for the current question will not be saved, if you navigate to another question directly by clicking on its question number. 5. You can view all the questions by clicking on the Question Paper button. Note that the options for multiple choice type questions will not be shown. BT 1/13

Formatting page ...
 

2013 BIOTECHNOLOGY BT Answering a Question 6. Procedure for answering a multiple choice type question: a. To select your answer, click on the button of one of the options b. To deselect your chosen answer, click on the button of the chosen option again or click on the Clear Response button c. To change your chosen answer, click on the button of another option d. To save your answer, you MUST click on the Save and Next button e. To mark the question for review, click on the Mark for Review and Next button. If an answer is selected for a question that is Marked for Review, that answer will be considered in the evaluation. 7. Procedure for answering a numerical answer type question: a. To enter a number as your answer, use the virtual numerical keypad b. A fraction (eg.,-0.3 or -.3) can be entered as an answer with or without 0 before the decimal point c. To clear your answer, click on the Clear Response button d. To save your answer, you MUST click on the Save and Next button e. To mark the question for review, click on the Mark for Review and Next button. If an answer is entered for a question that is Marked for Review, that answer will be considered in the evaluation. 8. To change your answer to a question that has already been answered, first select that question for answering and then follow the procedure for answering that type of question. 9. Note that ONLY Questions for which answers are saved or marked for review after answering will be considered for evaluation. BT 2/13

Top Contributors
to this ResPaper
(answers/comments)


namz

(10)

inigo_johnson

(4)

Sujithra Shankar

(3)

Pradeep Singh

(2)

Formatting page ...
 

2013 BIOTECHNOLOGY BT Paper specific instructions: 1. There are a total of 65 questions carrying 100 marks. Questions are of multiple choice type or numerical answer type. A multiple choice type question will have four choices for the answer with only one correct choice. For numerical answer type questions, the answer is a number and no choices will be given. A number as the answer should be entered using the virtual keyboard on the monitor. 2. Questions Q.1 Q.25 carry 1mark each. Questions Q.26 Q.55 carry 2marks each. The 2marks questions include two pairs of common data questions and two pairs of linked answer questions. The answer to the second question of the linked answer questions depends on the answer to the first question of the pair. If the first question in the linked pair is wrongly answered or is not attempted, then the answer to the second question in the pair will not be evaluated. 3. Questions Q.56 Q.65 belong to General Aptitude (GA) section and carry a total of 15 marks. Questions Q.56 Q.60 carry 1mark each, and questions Q.61 Q.65 carry 2marks each. 4. Questions not attempted will result in zero mark. Wrong answers for multiple choice type questions will result in NEGATIVE marks. For all 1 mark questions, mark will be deducted for each wrong answer. For all 2 marks questions, mark will be deducted for each wrong answer. However, in the case of the linked answer question pair, there will be negative marks only for wrong answer to the first question and no negative marks for wrong answer to the second question. There is no negative marking for questions of numerical answer type. 5. Calculator is allowed. Charts, graph sheets or tables are NOT allowed in the examination hall. 6. Do the rough work in the Scribble Pad provided. BT 3/13

Formatting page ...
 

2013 BIOTECHNOLOGY BT Q. 1 Q. 25 carry one mark each. Q.1 Under alkaline conditions, DNA is more stable than RNA because (A) RNA forms secondary structures (B) RNA is a single stranded molecule (C)RNA has uracil in place of thymidine (D)RNA is susceptible to hydrolysis Q.2 Which one of the following modifications is common toboth protein and DNA? (A) SUMOylation Q.3 (B) Nitrosylation (C)Methylation (D) Ubiquitination Protein A, which has strong affinity to Fc region of immunoglobulin, is extracted from (A)Saccharomyces cerevisiae (B)Staphylococcus aureus (C)Streptococcus pyogenes (D)Streptococcus sanguis Q.4 The first humanized monoclonal antibody approved for the treatment of breast canceris (A) Rituximab Q.5 (C) Bevacizumab (D) Herceptin Which one of the following aminoacids in proteins does NOT undergo phosphorylation? (A) Ser Q.6 (B) Cetuximab (B) Thr (C) Pro (D) Tyr The role of an adjuvant isto (A) prolong the persistence of antigen (B) cross link the antigen (C) increase the size of antigen (D) avoid inflammation Q.7 Endogenous antigens are presented on to the cell surface along with (A) MHC-II Q.8 (B) MHC-I (D) complement receptor Human genome sequencing project involved the construction of genomic library in (A)bacterial artificial chromosome (C) bacteriophage Q.9 (C) Fc receptor (B)pBR322 (D) pcDNA3.1 The nucleotide analogue used in DNA sequencing by chain termination method is (A) 1',3'-dideoxy nucleoside triphosphate (B) 2',3'-dideoxy nucleoside triphosphate (C) 2',4'-dideoxy nucleoside triphosphate (D) 2',5'-dideoxy nucleoside triphosphate Q.10 In nature, the horizontal gene transfer across bacteria is mediated by (A) gene cloning followed by transformation (C) conjugation only Q.11 Phylum proteobacteria is subdivided into -, -, -, - and -proteobacteria based on (A) G+C content (C)tRNA sequences BT (B)conjugation and transformation (D) transformation only (B) 23S rRNA sequences (D)16S rRNA sequences 4/13

Formatting page ...
 

2013 Q.12 BIOTECHNOLOGY BT Which one of the following is an ABC transporter? (A)multidrug resistance protein (C)bacteriorhodopsin Q.13 The catalytic efficiency for an enzyme is definedas (A) kcat Q.14 (B) (C) (B)46 or 50 (C) 74 or 86 (B)primase (D) DNA polymerase II The suitable substitution matrix to align closely related sequences is (A) PAM 250 or BLOSSUM 80 (C) PAM 120 or BLOSSUM 40 Q.17 (B) PAM 40 or BLOSSUM 80 (D) PAM 250 or BLOSSUM 40 1 1 2 1 3 0 ,Q and R ,which one of the following statements is TRUE? 2 2 2 2 1 3 If P (A) PQ = PR (C) QP = RP Q.18 If u log (A) (C) Q.19 (B) QR= RP (D) PQ = QR ), then + = (B) (D) 1 Hypophosphatemia is manifested by an X-linked dominant allele.What proportion of the offsprings from a normal male and an affected heterozygous female will manifest the disease? (A) sons and daughters (C) all sons and no daughters Q.20 (D) 84 or 108 The RNA primer synthesized during the replication process in bacteria is removed by (A) DNA gyrase (C) DNA polymeraseI Q.16 (D) Of the two diploid species, species I has 36 chromosomes and species II has 28 chromosomes. How many chromosomes would be found in an allotriploid individual? (A) 42 or 54 Q.15 (B) acetylcholine receptor (D) ATP synthase (B) all daughters and no sons (D) daughters and sons 10 4 is 18 12 One of theeigen values of P (A) 2 (B) 4 (C) 6 (D) 8 Q. 21 Q. 25 are of numerical answer type. Q.21 BT A callus of 5 g dry weight was inoculated on semi-solid medium for growth. The dry weight of the callus was found to increase by 1.5 fold after 10 days of inoculation. The growth index of the culture is _________ 5/13

Formatting page ...
 

2013 BIOTECHNOLOGY BT Q.22 A chemostat is operated at a dilution rate of 0.6 h-1. At steady state, the biomass concentration in the exit stream was found to be 30 g l-1. The biomass productivity (g l-1h-1) after 3h of steady state operation will be ___________ Q.23 A batch bioreactor is to be scaled up from 10 to 10,000 liters. The diameter of the large bioreactor is 10 times that of the small bioreactor. The agitator speed in the small bioreactor is 450 rpm. Determine the agitator speed (rpm) of the large bioreactor with same impeller tip speed as that of the small bioreactor. _________ Q.24 Calculate the percentage sequence identity for the pairwise alignment given below. _______ HELLO YELLOW Q.25 In a batch culture, the specific rate of substrate utilization is 0.25 g (g cell mass)-1 h-1 and specific rate of product formation is 0.215 g (g cell mass)-1 h-1. Calculate the yield of product from the substrate(Yp/s). ___________ Q. 26 to Q. 55 carry two marks each. Q.26 Match the commercial microbial sources in Group I with the products in Group II. Group I Group II P. Corynebacteriumlilium Q. Klebsiellaoxytoca R. Aspergillusniger S. Alcaligeneseutrophus 1. 2,3-Butane di-ol 2. Poly- -hydroxybutyric acid 3. Glutamic acid 4. Citric acid (A) P-3,Q-1,R-2,S-4 (C) P-1,Q-3,R-2,S-4 Q.27 (B) P-3,Q-1,R-4,S-2 (D) P-1,Q-3,R-4,S-2 Match the entries in the Group I with the elution conditions in Group II. Group I Group II P. Ion-exchange chromatography Q. Hydrophobic column chromatography R. Gel filtration chromatography S. Chromatofocusing 1. Isocratic solvent 2. Ampholytes 3. Increasing gradient of salt 4. Decreasing gradient of polarity (A) P-4,Q-1,R-2,S-3 (C) P-3,Q-4,R-1,S-2 BT (B) P-4,Q-3,R-1,S-2 (D) P-3,Q-4,R-2,S-1 6/13

Formatting page ...
 

2013 Q.28 BIOTECHNOLOGY BT Determine the correctness or otherwise of the following Assertion (a) and Reason (r). Assertion: Immobilization of plant cells can enhance secondary metabolite production during bioreactor cultivation. Reason: Immobilization protects the plant cells from shear forces in the bioreactor. (A) (B) (C) (D) Q.29 Both (a) and (r) are true and (r) is the correct reason for (a). Both (a) and (r) are true but (r) is not the correct reason for (a). (a) is true but (r) is false. (a) is false but (r) is true. Match the cell structures in Group I with the organismsin Group II. Group I Group II P. Endospores Q. Bipolar flagella R. Pseudomurine in cell wall S. Periplasmic flagella 1. Methanobacterium 2. Treponema 3. Spirillum 4. Clostridium (A) P-4, Q-3, R-1, S-2 (C) P-3, Q-4, R-1, S-2 Q.30 (B) P-4, Q-3, R-2, S-1 (D) P-4, Q-1, R-3, S-2 Match the antibioticsinGroup Iwith the targets inGroup II. Group I Group II P. Sulfonamide Q. Quinolones R. Erythromycin S. Cephalosporin 1. Peptidoglycan synthesis 2. Peptide chain elongation 3. Folic acid biosynthesis 4. Topoisomerase (A) P-3, Q-4, R-1, S-2 (C) P-4, Q-1, R-2, S-3 Q.31 (B) P-2, Q-4, R-3, S-1 (D) P-3, Q-4, R-2, S-1 In nature, Agrobacterium tumefaciens mediated infection of plant cells leads to P. crown gall disease in plants Q. hairy root disease in plants R. transfer of T-DNA into the plant chromosome S. transfer of Ri-plasmid into the plant cell (A) S only Q.32 (B) P and R only (C) Q and S only (D) Q only Match the entries inGroup I with the enzymes inGroup II. Group I Group II P. NAD+ Q. Selenium R. Pyridoxal phosphate S. Molybdenum 1. Glutathione peroxidase 2. Nitrogenase 3. Lactate dehydrogenase 4. Glycogen phosphorylase (A) P-3, Q-2, R-4, S-1 (C) P-3, Q-1, R-4, S-2 BT (B) P-4, Q-1, R-3, S-2 (D) P-3, Q-4, R-2, S-1 7/13

Formatting page ...
 

2013 Q.33 BIOTECHNOLOGY BT Match the herbicides in Group Iwith the target enzymesin Group II. Group I Group II P. Glyphosate Q. Bromoxynil R. Sulphonylureas S. Dalapon 1. Nitrilase 2. Acetolactatesynthetase 3. Dehalogenase 4. 5-Enolpyruvyl shikimate3-phosphate synthase (A) P-4, Q-1, R-2, S-3 (C) P-4, Q-3, R-2, S-1 Q.34 (B) P-2, Q-1, R-4, S-3 (D) P-3, Q-2, R-4, S-1 The activity of an enzyme was measured by varying the concentration of the substrate (S) in the presence of three different concentrations of inhibitor (I) 0, 2 and 4 mM.The double reciprocal plot given belowsuggests that the inhibitor (I) exhibits [I] = 4 mM [I] = 2 mM 1/Vo [I] = 0 mM 0 (A) substrate inhibition (C) mixed inhibition Q.35 1/[S] (B) uncompetitive inhibition (D) competitive inhibition Match the entries in Group Iwith the entries in Group II. Group I Group II P. RNAse P Q. RNase H R. snRNAs S. CstF 1. Polyadenylation 2. Splicing 3. Ribozymes 4. DNA-RNAhybrids (A) P-3, Q-4, R-2, S-1 (C) P-3, Q-2, R-1, S-4 Q.36 (B) P-4, Q-3, R-2, S-1 (D) P-2, Q-4, R-1, S-3 Determine the correctness or otherwise of the following Assertion (a) and Reason (r). Assertion:UPGMA method produces ultrametric tree. Reason:Sequence alignment is converted into evolutionary distances in UPGMA method. (A) Both (a) and (r) are true and (r) is the correct reason for (a) (B) Both (a) and (r) are true and (r) is not the correct reason for (a) (C) (a) is true but (r) is false (D) (a) is false but (r) is true BT 8/13

Formatting page ...
 

2013 Q.37 BIOTECHNOLOGY BT Match the entries in the Group Iwith the entries inGroup II. Group I Group II P. Threading Q. FASTA R. Profile S. Paralogs 1. Gene duplication 2. Fold prediction 3. HMM 4. k-tuple (A) P-2, Q-1, R-3, S-4 (C) P-3, Q-4, R-2, S-1 Q.38 Evaluate lim x tan x (A) Q.39 (B) 1 (C) 0 (C) (D) The solution of the following set of equations is (C) The solution to (B) (D) is (A) y = (c+x) cot x (C) y = (c + x) cosec x cot x Q.42 (D)-1 is (B) (A) Q.41 1 x The Laplace transform of (A) Q.40 (B) P-2, Q-4, R-3, S-1 (D) P-1, Q-4, R-3, S-2 (B) y = (c+x) cosec x (D) y = (c+x) A complete restriction digestion of a circular plasmid (5000bp) was carried out with HindIII,BamHIandEcoRIindividually. Restriction digestion yielded following fragments. Plasmid + HindIII 1200bp and3800bp Plasmid + BamHI 5000bp Plasmid + EcoRI 2500bp The number of sites for EcoRI,BamHIandHindIIIpresent on this plasmid are (A)EcoRI-2, BamHI-1, HindIII-2 (C)EcoRI-3, BamHI-2, HindIII-1 BT (B)EcoRI-1, BamHI-1, HindIII-2 (D)EcoRI-2, BamHI-2, HindIII-1 9/13

Formatting page ...
 

2013 BIOTECHNOLOGY BT Q. 43 Q. 47 are of numerical answer type. Q.43 The total number of fragments generated by the complete and sequential cleavage of the polypeptide given below by Trypsin followed by CNBr is _________ Phe-Trp-Met-Gly-Ala-Lys-Leu-Pro-Met-Asp-Gly-Arg-Cys-Ala-Gln Q.44 In a genetic study, 80 people were found to have alleles for polydactyly. Only 36 of them were polydactylous. What is the extent of penetrance percentage? ________ Q.45 One percent of the cars manufactured by a company are defective. What is the probability (upto four decimals) that more than two cars are defective, if 100 cars are produced? __________ Q.46 The maximum cell concentration (g l-1) expected in a bioreactor with initial cell concentration of 1.75 g l-1 and an initial glucose concentration of 125 g l-1 is (Yx/s = 0.6 g cell/g substrate) ________ Q.47 A fed batch culture was operated with intermittent addition of glucose solution at a flow rate of 200 ml h-1. The values of Ks, m and D are 0.3 g l-1, 0.4 h-1 and 0.1 h-1, respectively. Determine the concentration of growth limiting substrate (gl-1) in the reactor at quasi-steady state. ____________ Common Data Questions Common Data for Questions 48 and 49: A solution was prepared by dissolving 100 mg of protein X in 100 ml of water. Molecular weight of protein X is 15,000 Da; Avogadro s number = 6.022x 1023. Q.48 Calculate the molarity( M) of the resulting solution. (A)66.6 (C)0.67 Q.49 The number of moleculespresent in this solution is (A) 40.15x1019 BT (B)6.6 (D)0.067 (B) 6.023x1019 (C)4.015x1019 (D) 0.08x1019 10/13

Formatting page ...
 

2013 BIOTECHNOLOGY BT Common Data for Questions 50 and 51: The binding efficiency of three different receptorsR1, R2 and R3 were tested against a ligand using equilibrium dialysis, with a constant concentration of receptor and varying concentrations of ligand. The Scatchard plot of receptor titration with different concentration of ligand is given below (ris moles of bound ligand per moles of receptor and c is concentration of free ligand) 4 R1 3 R2 r/c 2 R3 1 R4 0 1 2 3 r Q.50 The number of ligand binding sites present on receptors R1 and R3, respectively are (A)1 and 4 Q.51 (B)1 and 1 (C)4 and 1 (D)2 and 2 Which one of the receptors has thehighestaffinity for the ligand? (A) R1 (B) R2 (C) R3 (D) R4 Linked Answer Questions Statement for Linked Answer Questions 52 and 53: A DNA fragment of 5000bp needs to be isolated from E.coli (genome size 4x103kb) genomic library. Q.52 The minimum number of independent recombinant clones required to represent this fragment in genomic library are (A) 16x102 Q.53 (B)12x102 (C) 8x102 (D) 1.25x102 The number of clones to represent this fragment in genomic library with a probability of 95% are (A) 5.9 x103 (B) 4.5x103 (C) 3.6 x103 (D) 2.4x103 Statement for Linked Answer Questions 54 and 55: During sterilization of a fermentation medium in a given bioreactor heating= 12.56, cooling = 7.48 and the total value of required for whole sterilization process is 52, where is the design criteria. Q.54 What is the value of holding? (A)31.96 Q.55 (C) 52.43 (D) 61.18 What is the holding period (min) at a k value of 3.36min-1? (A) 10.6 BT (B) 42.32 (B) 9.5 (C) 8.4 (D) 7.2 11/13

Formatting page ...
 

2013 BIOTECHNOLOGY BT General Aptitude (GA) Questions Q. 56 Q. 60 carry one mark each. Q.56 If (A) (B) and (C) (D) Q.57 then which of the following options is TRUE? The Headmaster ___________ to speak to you. Which of the following options is incorrect to complete the above sentence? (A) is wanting (B) wants (C) want (D) was wanting Q.58 Mahatama Gandhi was known for his humility as (A) he played an important role in humiliating exit of British from India. (B) he worked for humanitarian causes. (C) he displayed modesty in his interactions. (D) he was a fine human being. Q.59 All engineering students should learn mechanics, mathematics and how to do computation. I II III IV Which of the above underlined parts of the sentence is not appropriate? (A) I Q.60 (C) III (D) IV Select the pair that best expresses a relationship similar to that expressed in the pair: water: pipe:: (A) cart: road (C) sea: beach BT (B) II (B) electricity: wire (D) music: instrument 12/13

Formatting page ...
 

2013 BIOTECHNOLOGY BT Q. 61 to Q. 65 carry two marks each. Q.61 Velocity of an object fired directly in upward direction is given by is in seconds. When will the velocity be between 32 m/sec and 64 m/sec? (A) (1, 3/2) (C) (1/2, 3/2) Q.62 (B) (1/2, 1) , where (time) (D) (1, 3) In a factory, two machines M1 and M2 manufacture 60% and 40% of the autocomponents respectively. Out of the total production, 2% of M1 and 3% of M2 are found to be defective. If a randomly drawn autocomponent from the combined lot is found defective, what is the probability that it was manufactured by M2? (A) 0.35 Q.63 (B) 0.45 (C) 0.5 (D) 0.4 Following table gives data on tourists from different countries visiting India in the year 2011. Country USA England Germany Italy Japan Australia France Number of Tourists 2000 3500 1200 1100 2400 2300 1000 Which two countries contributed to the one third of the total number of tourists who visited India in 2011? (A) USA and Japan (B) USA and Australia (C) England and France (D) Japan and Australia Q.64 If (A) 30 Q.65 then the possible value of (B) -30 would be: (C) -42 (D) 42 All professors are researchers Some scientists are professors Which of the given conclusions is logically valid and is inferred from the above arguments: (A) All scientists are researchers (B) All professors are scientists (C) Some researchers are scientists (D) No conclusion follows END OF THE QUESTION PAPER BT 13/13

Formatting page ...
 

GATE 2013 : Answer keys for BT - Biotechnology Paper Q.No Key(s)/Value(s) Paper Q.No Key(s)/Value(s) BT 1 D BT 36 B BT 2 C BT 37 B BT 3 B BT 38 B BT 4 D BT 39 C BT 5 C BT 40 B BT 6 A BT 41 B BT 7 B BT 42 A BT 8 A BT 43 5 BT 9 B BT 44 45 BT 10 B BT 45 0.075 to 0.085 BT 11 D BT 46 76.7 to 76.9 BT 12 A BT 47 0.1 BT 13 C BT 48 A BT 14 B BT 49 Marks to All BT 15 C BT 50 D BT 16 B BT 51 A BT 17 A BT 52 C BT 18 D BT 53 D BT 19 A BT 54 A BT 20 C BT 55 B BT 21 0.5 BT 56 B BT 22 18 BT 57 C BT 23 45 BT 58 C BT 24 66.5 to 66.7 BT 59 D BT 25 0.81 to 0.91 BT 60 B BT 26 B BT 61 C BT 27 C BT 62 C BT 28 A BT 63 C BT 29 A BT 64 B BT 30 D BT 65 C BT 31 B BT 32 C BT 33 A BT 34 D BT 35 A

 

  Print intermediate debugging step

Show debugging info


 

Additional Info : Solved GATE exam paper study guide - GATE 2013 : Biotechnology free online question paper
Tags : GATE Biotechnology 2014 model question papers, syllabus, BT paper, India, GATE Exam Question Papers, Free Online Solutions, Answers, Answer Key, Graduate Aptitude Test in Engineering, IIT, IISc, GATE Exam Syllabus, GATE Study Material, GATE Exam Pattern, gate exam papers, gate question papers 2016, 2015, 2014, 2013, 2012, 2011, 2010, 2009, 2008, 2007, 2006, 2005, 2004, 2003, 2002, 2001, 2000, 1999, 1998, 1997, 1996, 1995, 1994, 1993, 1992, 1991, past gate papers, gate papers with answers, gate entrance exam engineering, gate previous years papers, gate old papers, gpat.  

© 2010 - 2017 ResPaper. Terms of ServiceContact Us Advertise with us

 

NEW: Save page on Android App
gate chat