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Mathematics 2012 board paper

(2,1)


sarayumbharadwaj 23 mins ago
ICSE 2014 : COMPUTER APPLICATIONS
double
aarish_hasan 51 mins ago
ICSE 2014 : SCIENCE Paper 3 (Biology)

depletion of ozone


yashu5 5 hours ago
GATE 2014 : Chemical Engineering

The answer might be strength


farhanresearcher 8 hours ago
ISC Specimen 2011 Computer Science Paper 1 (Theory)

F=A'B+AB'C+A

=A+B+AB'C

=A(1+B'C)+B

=A+B


tejaswini26 9 hours ago
Geography ICSE 2014

Jharkhand


chirag99 12 hours ago
Physics ICSE 2014

Isotone


amrit5 1 day ago
ICSE 10th board maths paper 2013

P1 V1 / T= P2 V2 / T2      (for an ideal gas)

T1 = 27 + 273 = 300 K and T2 = 327 + 273 = 600 K. Substituting gives

V2 = (P1 / P2) (T2 / T1) V= (1 / 2) (600 / 300) V= V1.

Since V= V1, volume remains same, i.e., 4 liters. 

 

 


bsl 1 day ago
ISC Specimen 2011 Mathematics

Take √x = t,

Then dt/dx = 1/(2√x )

So, dt/dx = 1/2t

Therefore, dx = 2tdt

Replacing √x with t and dx with 2tdt, we get:

∫2tsintdt

Now we can integrate by parts and we get:

2t∫sintdt - ∫[{2d(t)/dt}{∫sintdt}]dt + c

= 2t(-cost) - ∫(2(-cost))dt

= -2tcost + 2sint

= -2√xcos√x + 2sin√x


vivek_venkat_subramaniam 2 days ago
Mathematics 2012 board paper

(i) ABCD IS  A CYCLIC QUAD

so DCB+ DAB = 180  (sum of opp angles of cyclic quadrilateral is supplementary)

ang DAB = 50

(ii)  join DB

angle ADB = 90 (angle in  a semicircle is 90 )

in triangle ADB     50 + 90+ angDBA = 180

hence angle DBA = 40


scorewellmarks_2014 2 days ago

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