see....,
arc CD subtends 25^{0} at circum ference so it subtends 50^{0 }
therefore angle AOC =50^{0}
ABCD
therefore <ABC=<BCD(INTERRIOR ALTERNATE)
now, consider arc BD it subtends at c to form 25^{0} so, at center it will subtend 50^{0}....
<AOC=<BOD=50^{0}
sayan38 2 years ago
