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## Homework Statement

The rotational inertia for a diver in a pike position is about 15.5 kg m2; it is only 8.0 kg m2 in a tucked position (the figure above).

(a) If the diver gives himself an initial angular momentum of 106 kg m2/s as he jumps off the board, how many turns can he make when jumping off a 10.0-m platform in a tuck position? [Hint: Gravity exerts no torque on the person as he falls; assume he is rotating throughout the 10.0 m dive.]

3.0

4.0

2.0

5.0

4.5

(b) How many in a pike position?

1.2

1.8

1.6

1.1

1.4

## Homework Equations

W

_{i}I

_{i}= W

_{f}I

_{f}

n= (w

_{f}/2Pie) t

## The Attempt at a Solution

The teacher mildly went over this problem in class. These are the eqns he gave us. I tried to solve for w

_{f}and substituted that answer in the second eqn to find the number of turns in time t, which i calculated thru the eqn :

h=v

_{i}t + 1/2 at

^{2}

I really have NO idea how to do this problem, i only know these eqns from wat the instructor provided. If you can please teach me how to go about solving the problem and understanding it, i would really truly appreciate it!! Thanks!