


when it departs from the rocket, the velocity of the stone would be 50*3=150m/s.
Now lets assume that the point of depart of the stone be the base.
During it's downward journey after reaching the topmost point, the velocity at the same point again becomes 150m/s in the downward direction.
Further find the distance of depart of stine from the ground=1/2*50*9=225m.
Finally, v^2=150*150+2*g*225=22500+4500=27000
v=sqrt(27000)=30*sqrt(30) m/s.
ashutosh_dash 295 days ago



bro, how much marks would be deducted if written diastole instead of joint diastole?
ashutosh_dash 327 days ago



Bro, there is no trial ball in real international matches.. It is just a Gully Cricket experience..
ashutosh_dash 327 days ago


