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0.01v + 0.2 * 0 = 0.01 * 100 + 0.2*20

-> v = 500m/s

!!!  t=1s

net external force is zero

this implies->

body is at rest or having uniform velocity

net torque may or may not be zero

now,

from the above 2 points its clear that

a - linear momentum does not change

b,d - potential and kinetic energy may or may not CHANGE

c- as details about net torque is not given we cant say anything about angular momentum

[(ma + ma + m(-a)]/m+m+m+m+6m

= a/10

use law of conservation of mechanical energy

1/2kx^2 = 1/2*4ky^2

=> y/x = 1/2

trial and error method:-

kinetic energy of ball is zero when it touches the ground so c is discarded

kinetic energy increases considerably till it touches the ground (as velocity increases due to acceleration due to gravity). therefore a and d are discarded.

answer is B

the answer is from  my text book (selina publishers)

not 2016 prelims...

check yolomama contributions in chemistry 2014 papers

connects between*

i esteem ur comment