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Correct me if I am wrong but it looks icy during winter as it's freezing temperature is 15ish degree celsuis.

(8)^1/2

log[(x^2+1)/(x^2+3)]^1/2

(A) (-infinity,-2) U (3,infinity)

(B)(-2,3)

0 is the identity element

determinant of adjoint is |determinant|^2=4^2=16

p=-2

y=-6