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  ICSE Class X Prelims 2025 : Computer Applications (Nalanda International School, Vadodara)

  Here's a Java class that declares an array to accept and store ten words, and displays only those words that begin and end with 'A' or 'a': public class WordFilter { private String[] words; public WordFilter() { words = new String[10]; } public void inputWords() { java.util.Scanner scanner = new java.util.Scanner(System.in); System.out.println("Enter 10 words:"); for (int i = 0; i < 10; i++) { words[i] = scanner.nextLine(); } scanner.close(); } public void displayFilteredWords() { System.out.println("Words beginning and ending with 'A' or 'a':"); for (String word : words) { if (word.toLowerCase().startsWith("a") && word.toLowerCase().endsWith("a")) { System.out.println(word); } } } public static void main(String[] args) { WordFilter filter = new WordFilter(); filter.inputWords(); filter.displayFilteredWords(); } } This class does the following: 1. Declares an array 'words' to store ten words. 2. Provides a method 'inputWords()' to accept input from the user. 3. Implements a method 'displayFilteredWords()' that checks each word in the array and displays only those that begin and end with 'A' or 'a'. 4. Includes a main method to create an instance of the class and call the necessary methods. The program will display words like "Anita", "Amrita", "Alina", and "AMITHA" from the given example, as they all start and end with 'A' or 'a'. pandurang2

  ISC Class XII Prelims 2025 : Computer Science (Hiranandani Foundation School (HFS), Powai, Mumbai)

  Here's a description of how to complete the full adder circuit diagram: (i) Add an XOR gate with inputs A and B, and connect its output to one input of another XOR gate. (ii) Connect C_in to the other input of the second XOR gate. The output of this gate will be the Sum. (iii) Add an AND gate with inputs A and B. (iv) Add another AND gate with inputs from the output of the first XOR gate and C_in. (v) Finally, add an OR gate that takes inputs from both AND gates. The output of this OR gate will be C_out. This configuration creates a full adder circuit capable of adding three 1-bit binary numbers (A, B, and C_in) and producing a Sum and Carry-out (C_out). Reasoning: A full adder requires two XOR gates for calculating the Sum, two AND gates for determining carry conditions, and one OR gate to combine the carry possibilities. This arrangement allows for proper addition of three binary inputs while accounting for both Sum and Carry-out. bhagyashree70

  + 5 more by bhagyashree70  

  ISC Class XII Prelims 2025 : Computer Science (Hiranandani Foundation School (HFS), Powai, Mumbai)
  	(1) NOT gate (2) OR gate (3) AND gate To derive the Boolean expression F: F = (A' + B) · C Where A' represents the NOT of A. This expression is already in its simplified form. The circuit performs the following operations: 1. Inverts A 2. ORs the result with B 3. ANDs the result with C No further simplification is possible for this expression. bhagyashree70

  ISC Class XII Prelims 2025 : Computer Science (Hiranandani Foundation School (HFS), Powai, Mumbai)

  (b) AND gate This diagram represents an AND gate, which is one of the basic logic gates in digital circuits. The shape shown is the standard symbol for an AND gate, with two inputs on the left side and one output on the right side. The AND gate produces a HIGH (1) output only when all of its inputs are HIGH (1). Otherwise, it produces a LOW (0) output. This gate is fundamental in digital logic design and is used to perform the logical AND operation. bhagyashree70

  ISC Class XII Prelims 2025 : Computer Science (Hiranandani Foundation School (HFS), Powai, Mumbai)

  To reduce X(E,R,S,C) using Karnaugh's map and draw the logic gate diagram: 1. Create the Karnaugh map: RS\EC | 00 | 01 | 11 | 10 ------+----+----+----+---- 00 | 1 | 1 | 1 | 1 01 | 1 | 1 | 1 | 1 11 | 0 | 0 | 1 | 1 10 | 1 | 1 | 1 | 1 2. Identify the largest groups of 1s: - One group of 8 (covers all 1s except the two 0s) - One group of 2 (covers the two 1s in the bottom right) 3. Write the reduced SOP expression: X = R' + C 4. Draw the logic gate diagram: - Use one 2-input OR gate - Connect R' (R with a NOT gate) to one input - Connect C directly to the other input - The output of the OR gate is X The logic gate diagram would consist of: - One NOT gate with R as input - One 2-input OR gate with R' and C as inputs - The output of the OR gate is the final output X This reduced expression significantly simplifies the original function, requiring only two gates to implement. bhagyashree70

  ISC Class XII Prelims 2025 : Computer Science (Hiranandani Foundation School (HFS), Powai, Mumbai)

  (b) Both A and R are true, and R is not the correct explanation of A. Reasoning: Assertion (A) is true: Recursion is indeed implemented using function calls. In recursive algorithms, a function calls itself to solve smaller instances of the same problem. Reason (R) is also true: The absence of a base case in a recursive function does lead to infinite recursion. A base case is necessary to stop the recursive calls and prevent the function from calling itself indefinitely. However, R is not the correct explanation of A. The fact that recursion is implemented using function calls is not directly related to or explained by the statement about the absence of a base case leading to infinite recursion. These are two separate, true statements about recursion, but one does not explain the other. Therefore, option (b) is the correct answer, as both statements are true, but R is not the correct explanation of A. bhagyashree70

  ICSE Class X Prelims 2025 : Computer Applications (Nalanda International School, Vadodara)

  Here's a Java class that accepts values in an integer array of size 10, calculates the sum of one-digit and two-digit numbers separately, and displays the results: public class NumberSumCalculator { private int[] numbers; public NumberSumCalculator() { numbers = new int[10]; } public void inputNumbers() { java.util.Scanner scanner = new java.util.Scanner(System.in); System.out.println("Enter 10 integer values:"); for (int i = 0; i < 10; i++) { numbers[i] = scanner.nextInt(); } scanner.close(); } public void calculateAndDisplaySums() { int sumOneDigit = 0; int sumTwoDigit = 0; StringBuilder oneDigitNumbers = new StringBuilder(); StringBuilder twoDigitNumbers = new StringBuilder(); for (int num : numbers) { if (num > = 0 && num < 10) { sumOneDigit += num; oneDigitNumbers.append(num).append(" + "); } else if (num > = 10 && num < 100) { sumTwoDigit += num; twoDigitNumbers.append(num).append(" + "); } } System.out.println("Sum of one digit numbers : " + oneDigitNumbers.substring(0, oneDigitNumbers.length() - 3) + "= " + sumOneDigit); System.out.println("Sum of two digit numbers : " + twoDigitNumbers.substring(0, twoDigitNumbers.length() - 3) + "= " + sumTwoDigit); } public static void main(String[] args) { NumberSumCalculator calculator = new NumberSumCalculator(); calculator.inputNumbers(); calculator.calculateAndDisplaySums(); } } This class does the following: 1. Defines an array 'numbers' to store 10 integer values. 2. Provides a method 'inputNumbers()' to accept user input for the array. 3. Implements 'calculateAndDisplaySums()' method to separate one-digit and two-digit numbers, calculate their sums, and display the results. 4. The main method creates an instance of the class and calls the necessary methods. When run, this program will prompt the user to enter 10 numbers, then calculate and display the sums as required. bhagyashree70

  ICSE Class X Prelims 2025 : Biology (Jamnabai Narsee School (JNS), Mumbai)

  The correct sequence of events during cell division (mitosis) is: 1. Chromosomes line up in one plane 2. Spindle fibres disappear 3. Sister chromatids separate 4. Nucleolus disappears 5. Formation of daughter cells Reasoning: This sequence represents the key events of mitosis in chronological order. First, chromosomes align at the metaphase plate. Then, as anaphase begins, sister chromatids separate and move to opposite poles as spindle fibers contract. The nucleolus typically disappears during prophase and reforms during telophase. Finally, cytokinesis results in the formation of two daughter cells. sadaf28

  + 1 more by sadaf28  

  ICSE Class X Prelims 2025 : Biology (Jamnabai Narsee School (JNS), Mumbai)

  The correct sequence for the male reproductive system is: Testis, Sperm duct, Bulbo-urethral gland The correct sequence for the female reproductive system is: Fallopian tube, Cervix Reasoning: This arrangement follows the logical flow of gamete production and movement through the reproductive system. In males, sperm is produced in the testis, travels through the sperm duct, and the bulbo-urethral gland secretes fluid during ejaculation. In females, the egg travels through the fallopian tube and then passes through the cervix. sadaf28

  ICSE Class X Prelims 2025 : Biology (Jamnabai Narsee School (JNS), Mumbai)
  	The hormone secreted by the alpha cells of the pancreas is glucagon. Glucagon is responsible for raising blood sugar levels when they are too low. abcdclass10_icse

  + 4 more by abcdclass10_icse  

  ICSE Class X Prelims 2025 : Biology (Jamnabai Narsee School (JNS), Mumbai)
  	Homo Habilis, Homo Erectus, Homo Neanderthal, Cro-Magnon, Homo Sapiens This sequence represents the generally accepted chronological order of human evolution, from earlier to more recent species. abcdclass10_icse

  ICSE Class X Prelims 2025 : Biology (Jamnabai Narsee School (JNS), Mumbai)
  	Platelets, Thromboplastin, Prothrombin, Thrombin, Fibrinogen, Fibrin This sequence represents the order of events in blood clotting, starting with the aggregation of platelets and ending with the formation of fibrin, which creates the clot. abcdclass10_icse

  ICSE Class X Prelims 2025 : Biology (Jamnabai Narsee School (JNS), Mumbai)
  	Cornea, Aqueous Humour, Pupil, Eye lens, Vitreous Humour This sequence follows the path of light as it enters and passes through the eye, from the outermost structure to the innermost. abcdclass10_icse

  ICSE Class X Prelims 2025 : Biology (Jamnabai Narsee School (JNS), Mumbai)
  	The hormone secreted by alpha cells stimulates the breakdown of glycogen in the liver to raise the blood sugar level. Glycogen is a stored form of glucose in the liver, and glucagon triggers its conversion back to glucose, which is then released into the bloodstream to increase blood sugar levels. abcdclass10_icse

  ICSE Class X Prelims 2024 : Chemistry (Karnataka ICSE Schools Association KISA, Bengaluru)
  	(c) shaurrkayy

  + 1 more by shaurrkayy  

  ICSE Class X Prelims 2024 : Chemistry (Karnataka ICSE Schools Association KISA, Bengaluru)
  	(d) Only P shaurrkayy

  ICSE Class X Prelims 2025 : Chemistry (Delhi Public School (DPS), Newtown, Kolkata)
  	Ans (d) Reason: (a) 3.764×10233.764 \times 10^{23}3.764×1023 (b) 6.865×10226.865 \times 10^{22}6.865×1022 (c) 6.022×10226.022 \times 10^{22}6.022×1022 (d) 6.022×10236.022 \times 10^{23}6.022×1023 1 gram atom = 1 mole of atoms. For diatomic chlorine, 2 gram atoms correspond to 1 mole of Cl2 molecules. Number of molecules = 1×6.022×1023=6.022×1023 = 6.022x1023 arnavxii

  + 45 more by arnavxii  

  ICSE Class X Prelims 2025 : Chemistry (Delhi Public School (DPS), Newtown, Kolkata)
  	Ans d) Only R arnavxii

  ICSE Class X Prelims 2024 : Chemistry (Bishop Moore Vidyapith (BMVM), Mavelikara, Alappuzha)
  	Ans (a) Rubidium Li > Na > K > Rb Rubidium ($Rb$) has the largest atomic size and the weakest attraction between the nucleus and the outermost electron, resulting in the lowest ionization potential. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Balanced chemical equations for the given conversions: a) 4Fe(OH)2 + O2 + 2H2O → 4Fe(OH)3 b) 2Fe(OH)3 → Fe2O3 + 3H2O c) Fe(OH)2 + 2HCl → FeCl2 + 2H2O Chemical formulas of the given compounds: a) Oleum: H2S2O7 b) Iron pyrite: FeS2 c) Sodium argentocyanide: Na[Ag(CN)2] arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	ii) The balanced chemical equation for the oxidation of phosphorus to phosphoric acid by concentrated nitric acid is: P4 + 20HNO3 → 4H3PO4 + 20NO2 + 4H2O This reaction involves the oxidation of phosphorus (P) to phosphoric acid (H3PO4) by concentrated nitric acid (HNO3). The nitric acid is reduced to nitrogen dioxide (NO2) in the process. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	The type of bond formed between atoms of non-metallic elements having a large difference in their electronegativities is an ionic bond. Sodium chloride (NaCl): Sodium (𝑁𝑎) has low electronegativity, and chlorine (𝐶𝑙) has high electronegativity. The large difference causes sodium to lose an electron to chlorine, forming an ionic bond. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)

  i) Two advantages of the special funnel arrangement for absorbing HCl in water are: 1. It prevents the backflow of water into the reaction vessel. 2. It allows for efficient absorption of the gas by providing a large surface area for gas-liquid contact. ii) Number of molecules in gas 'Q': Volume of gas 'P' = 1.2 L = 1200 c.c. Volume of gas 'Q' = 400 c.c. Using the proportion: 1200 c.c. : X molecules = 400 c.c. : Y molecules Y = (400 × X) ÷ 1200 = X ÷ 3 Therefore, gas 'Q' will contain X/3 molecules. The law that forms the basis of this calculation is Avogadro's Law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	a) Cation: NH₄⁺ (ammonium) Anion: SO₄²⁻ (sulfate) b) The anion that gives a white precipitate with BaCl₂ solution but is soluble in dilute HCl is CO₃²⁻ (carbonate). arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	iv) The salt 'X' is likely an ammonium salt. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	a) Pb²⁺ + 2e⁻ → Pb b) CuSO₄ + 2NH₃ + 2H₂O → Cu(OH)₂ + (NH₄)₂SO₄ c) P₄ + 5O₂ + 6H₂O → 4H₃PO₄ arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	iii) Balanced chemical equations: arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	ii) a) Volume of 320 g of SO₂: Molar mass of SO₂ = 32 + (2 × 16) = 64 g/mol Number of moles = 320 g ÷ 64 g/mol = 5 moles Volume at STP = 5 × 22.4 L = 112 L b) Mass of 10²² atoms of Sulphur: Mass = (10²² ÷ 6 × 10²³) × 32 g = 0.533 g arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	a) Column A: Lead (II) hydroxide, dil. Nitric acid Column B: 4. neutralization b) Column A: Magnesium, dil. Hydrochloric acid Column B: 3. displacement c) Column A: Calcium chloride, Sodium carbonate Column B: 1. precipitation Reasoning: The reactions are matched based on the typical methods used to prepare salts from the given reactants. i) a) Duralumin (Al+Mg+Mn+Cu) b) Brass (Cu+Zn+Sn) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)

  a) The electrode 'Y' needs to be continuously replaced because it is consumed during the electrolysis process. In the Hall-Heroult process for aluminum production, the carbon anode (electrode Y) reacts with oxygen ions to form carbon dioxide gas, gradually eroding the electrode. b) The reaction taking place at electrode 'Z' (cathode) is: Al³⁺ + 3e⁻ → Al c) The molecular formulae of the constituents of the electrolytic mixture are: - Al₂O₃ (alumina) - Na₃AlF₆ (cryolite) - AlF₃ (aluminum fluoride) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	ii) To determine the empirical formula: C: 26.59/12 = 2.22 H: 2.22/1 = 2.22 O: 71.19/16 = 4.45 Dividing by the smallest value (2.22): C: 1, H: 1, O: 2 The empirical formula is CHO2. iii) The Hall-Heroult process is used for the electrolytic production of aluminum from alumina (Al2O3) dissolved in molten cryolite (Na3AlF6). arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	The black colored compound 'X' is likely copper(II) oxide (CuO). The balanced equation for the reaction is: CuO + 2HCl → CuCl2 + H2O Copper(II) oxide reacts with concentrated hydrochloric acid to form copper(II) chloride, which gives a blue colored solution. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	To find the molecular weight of gas 'X': Weight of 1L H2 at STP = 0.09g Weight of 1L gas 'X' at STP = 3.15g Molecular weight of 'X' = (3.15 / 0.09) × 2 = 70 g/mol The molecular weight of gas 'X' is 70 g/mol. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	The atomic numbers of elements X, Y, and Z are 7, 13, and 10 respectively. This means: X is Nitrogen (N) Y is Aluminum (Al) Z is Neon (Ne) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	a) X2 molecule (likely N2): X : X ::: b) Y2 molecule: Y - Y arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	a) Element X (Nitrogen) combines with Hydrogen to form a basic gas (NH3, ammonia). b) Element Z (Neon) will have the highest ionization potential, as it is a noble gas with a complete outer shell. c) Element Y (Aluminum) forms an ionic compound with Chlorine (AlCl3). arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	b) Cu(NO3)2 → CuO + 2NO2 + 1/2O2 This is the thermal decomposition of copper(II) nitrate. c) KHC03 + H2SO4 (dil.) → KHSO4 + H2O + CO2 Potassium hydrogen carbonate reacts with dilute sulfuric acid to produce potassium hydrogen sulfate, water, and carbon dioxide. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	To find the molecular weight of gas 'X': 1. We know that 1 L of H2 weighs 0.09 g at STP 2. Molecular weight of H2 = 2 g/mol 3. Weight of 1 L of 'X' at STP = 3.15 g Using the ratio: (0.09 g / 2 g/mol) = (3.15 g / Molecular weight of 'X') Molecular weight of 'X' = (3.15 × 2) / 0.09 = 70 g/mol Therefore, the molecular weight of gas 'X' is 70 g/mol. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	The reactant is copper(II) oxide (CuO). Balanced equation: CuO + 2HCl → CuCl2 + H2O Reasoning: The black colored compound 'X' is likely copper(II) oxide. When it reacts with concentrated hydrochloric acid, it forms copper(II) chloride, which gives a blue color in solution. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	a) Ca3N2 + 6H2O → 3Ca(OH)2 + 2NH3 b) 2Cu(NO3)2 → 2CuO + 4NO2 + O2 c) 2KHC03 + H2SO4 → K2SO4 + 2CO2 + 2H2O arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	The electron dot structure for the formation of the positive ion (ammonium ion, NH4+) from ammonia: H | H-N:-H + H+ → H-N+-H | | H H The lone pair on the nitrogen atom in ammonia accepts a proton (H+) to form the ammonium ion (NH4+). arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	1. Nitrogen dioxide (NO2) 2. Chlorine (Cl2) 3. Oxygen (O2) Reasoning: 1. Copper reacts with cold, dilute nitric acid to produce nitrogen dioxide gas. 2. Manganese dioxide reacts with concentrated hydrochloric acid to produce chlorine gas. 3. Electrolysis of acidified water produces oxygen gas at the anode. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	e) Al2O3 Reasoning: Corundum is a crystalline form of aluminum oxide with the chemical formula Al2O3. It is known for its hardness and is used as an abrasive and in gemstones like rubies and sapphires. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	d) Reduced to HCl Reasoning: When ammonia is mixed with chlorine in excess, chlorine is reduced to HCl. The overall reaction is: 2NH3 + 3Cl2 → N2 + 6HCl arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	c) Higher Reasoning: A higher concentration of ions in solution increases the probability of ions being discharged at their respective electrodes due to greater availability and mobility of ions. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	b) Methane Reasoning: Methane (CH4) is a nonpolar molecule and does not conduct electricity in the gaseous state. Ammonia (NH3) is polar and can conduct electricity to some extent in the gaseous state. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	a) Largest atomic size among all the elements of the same period. Reasoning: Within a period, atomic size generally decreases from left to right due to increasing nuclear charge and ineffective shielding by electrons in the same shell. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)

  ii) Matching: a) Funnel arrangement - 6. Liquid ammonia b) Calamine - 4. Zinc carbonate c) Brown ring test - 1. Nitroso iron[II]sulphate d) Non-volatile acid - 5. Sulphuric acid e) Cleansing agent - 3. Liquor ammonia Reasoning: a) Funnel arrangement is used for adding liquid ammonia in layer formation tests. b) Calamine is a zinc carbonate-based medication. c) Brown ring test uses nitroso iron(II) sulphate to detect nitrates. d) Sulphuric acid is a common non-volatile acid. e) Liquor ammonia (ammonia solution) is used as a cleansing agent. iii) a) If an element has seven valence electrons, it is likely to have the valency of 1. Reasoning: An element with seven valence electrons needs one more electron to complete its octet. Therefore, it tends to gain one electron, giving it a valency of 1 (negative). This is typical for halogens in Group 17 of the periodic table. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans c) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)

  c) P−Fe   , Q−Zn ,  R−AgR - Ag P - Solution turns green: The green color is likely due to the formation of ferrous sulphate (FeSO4) which suggests that  P is iron (Fe) displacing copper (from copper sulphate (CuSo4)   Q - Solution becomes colorless: The solution turning colorless indicates that Q completely displaced copper, leaving no colored ions in the solution. This suggests Q is zinc (𝑍𝑛) which is more reactive than copper and displaces it fully.   R - Solution remains blue: If the solution remains blue, it means R is less reactive than copper and does not displace it. This is indicative of silver (𝐴𝑔) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)

  a) 11g At STP, 1 mole of any gas occupies 22.4 liters. Step 2: Molar mass of ammonia (NH₃) Nitrogen (N) = 14 g/mol Hydrogen (H) = 1 g/mol × 3 = 3 g/mol Thus, the molar mass of NH₃ = 14 + 3 = 17 g/mol. Step 3: Number of moles in 14.5 liters Moles of NH₃=Volume at STP /Molar volume at STP =14.5/22.4≈0.647 moles   Step 4: Mass of NH₃ Mass=Moles × Molar mass=0.647×17≈11 g Final Answer: a) 11 g arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	d) solubility. The hydrolytic method of concentration involves the separation of ore particles based on their difference in solubility in water or other liquid mediums. It works on the principle that the gangue (impurities) and ore particles have differing solubility, allowing for their separation through washing or dissolution. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans a) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans c) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans c) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans b) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans d) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans c) Argon arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans d) arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)

  c) Both A and B are correct Reasoning: This answer is correct because: 1. Assertion (A) is correct: Pb(OH)Cl is indeed a basic salt. A basic salt is formed when a strong base reacts with a weak acid, or when a base is not completely neutralized by an acid. In this case, Pb(OH)Cl still contains an OH- group, which can release hydroxide ions in solution, making it basic. 2. Reason (R) is also correct, but it describes the formation of an acidic salt rather than a basic salt. The statement "The OH- ions of Pb(OH)2 are partially replaced by H+ ions of acid" is accurate in describing how an acidic salt would form. However, this process is not directly related to the formation of Pb(OH)Cl as a basic salt. Although the reason (R) does not directly explain why Pb(OH)Cl is a basic salt, both statements are independently correct. arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	a) Only A is correct arnavxii

  ICSE Class X Prelims 2025 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Ans D) Zinc Chloride Zinc chloride forms a white precipitate with NH₄OH, but it is soluble in excess NH₄OH, forming a zinc-ammonia complex: arnavxii

  ICSE Class X Prelims 2025 : History and Civics (Pawar Public School (PPS), Kandivali, Mumbai) : Prelim 2
  	(b) December 30, 1906 raindelu

  + 6 more by raindelu  

  ICSE Class X Prelims 2025 : History and Civics (Pawar Public School (PPS), Kandivali, Mumbai) : Prelim 2
  	(d) (A) : iv, (B) iii, (C): ii, (D) i raindelu

  ICSE Class X Prelims 2025 : History and Civics (Pawar Public School (PPS), Kandivali, Mumbai) : Prelim 2
  	(d) Quo- warranto raindelu

  ICSE Class X Prelims 2025 : History and Civics (Pawar Public School (PPS), Kandivali, Mumbai) : Prelim 2
  	(a) R contradicts A raindelu

  ICSE Class X Prelims 2025 : History and Civics (Pawar Public School (PPS), Kandivali, Mumbai) : Prelim 2
  	(c) R and S raindelu

  ICSE Class X Prelims 2025 : History and Civics (Pawar Public School (PPS), Kandivali, Mumbai) : Prelim 2
  	(d) Jagdeep Dhankhar raindelu

  ICSE Class X Prelims 2025 : History and Civics (Pawar Public School (PPS), Kandivali, Mumbai) : Prelim 2
  	(b) Adjournment Motion raindelu

  ICSE Class X Prelims 2025 : English Paper 2 (English Literature) (Dhirubhai Ambani International School (DAIS), Mumbai)
  	D vanshika_d

  + 2 more by vanshika_d  

  ICSE Class X Prelims 2025 : English Paper 2 (English Literature) (Dhirubhai Ambani International School (DAIS), Mumbai)
  	C vanshika_d

  ICSE Class X Prelims 2025 : English Paper 2 (English Literature) (Dhirubhai Ambani International School (DAIS), Mumbai)
  	B vanshika_d

  ICSE Class X Prelims 2025 : Geography (Villa Theresa High School (VTS), Mumbai)

  (b) Soil erosion occurs more frequently during the monsoon season. Reasoning: During monsoon season, heavy rainfall and strong winds are common. These conditions lead to increased soil erosion for several reasons: 1. Heavy rain can dislodge soil particles and wash them away. 2. Increased water flow in rivers and streams can erode banks. 3. Strong winds can carry away loose topsoil, especially in dry areas. 4. Saturated soil is more susceptible to landslides and mass movements. (c) Red soil needs fertilization for better agricultural productivity. Reasoning: Red soils are typically: 1. Low in organic matter and nutrients, especially nitrogen and phosphorus. 2. Often acidic, which can limit nutrient availability to plants. 3. Prone to leaching of nutrients due to their high iron oxide content. 4. Often found in tropical and subtropical regions with high rainfall, which can wash away nutrients. Fertilization helps overcome these limitations by: 1. Adding essential nutrients to the soil. 2. Improving soil structure and water retention capacity. 3. Neutralizing soil acidity if lime is added along with fertilizers. 4. Enhancing microbial activity in the soil, which aids in nutrient cycling. prashy22533

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