According to the given question,
(xiy) (3+5i) = 6+24i
3x+5xi3iy5i^{2}y = 6+24i
3x+(5x3y)i5(1)y = 6+24i
3x+5y + (5x3y)i = 6+24i
By equating the real and imaginary parts on both sides,we get
3x+5y=6 and
5x3y=24
By solving the above two equations, we get
x=3 and y=3
coolboys98657 20 days ago
